Þu þekilde istediðim þekilde çalýþtý;

 if ((mysql_num_rows($result)>1) and !(($x == 9) or ($x == 0)))

Saygýlarýmla..

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> yalnýz orada 9 olan deðer 0'a da eþit olmama þartýný saðlayacaktýr.
> oraya dikkat edin bence<br>
> or matýksalýnda bir doðru olmasý yeterli biliyorsunuz.<br>
> <br>
> Bedreddin SAHBAZ wrote:
> <blockquote
> cite="mid:be6a3ab7c255b592f814d9b4f114b711.squirrel_at_posta.sahbaz.name.tr"
> type="cite">
> <pre wrap="">9 girdiðim zaman x!=9 þartýna göre false almam lazým, ve
> arada or olduðuna
> göre bu false yüzünde if false deðeri ile iþlem-2'yi yapmalý. Ancak bu
> þekilde çalýþmýyor.
>
>
>
> </pre>
> <blockquote type="cite">
> <pre wrap="">&lt;!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01
> Transitional//EN"&gt;
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> &lt;head&gt;
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> if yapýsýnda basit mantýksal hata var sadece&lt;br&gt;
> 9 eþit bir deðiþken girdiðinde zaten senin yapýna göre&lt;br&gt;
> iþlem 1 çalýþmasý lazým... çünkü 9 a eþit deðilse demiþsin...&lt;br&gt;
> bir de 0 a eþit deðil demiþsin...&lt;br&gt;
> &lt;br&gt;
> &lt;br&gt;
> Bedreddin SAHBAZ wrote:
> &lt;blockquote
> cite=<a class="moz-txt-link-rfc2396E"
> href="mailto:mid:9a81e299ce6b22852043a7be26e09ea7.squirrel_at_posta.sahbaz.name.tr">"mid:9a81e299ce6b22852043a7be26e09ea7.squirrel_at_posta.sahbaz.name.tr"</a>
> type="cite"&gt;
> &lt;pre wrap=""&gt;Merhaba Arkadaþlar,
>
> Bir saattir basit bir IF yapýsýna takýldým kaldým
>
> if ((mysql_num_rows($result)&amp;lt;1) or ($x != 9) or ($x != 0))
> {
> iþlem-1
> }
> else
> {
> iþlem-2
> }
>
> mysql'de sonuç boþ geldi ise veya x 9'a eþit deðilse veya x 0'a eþit
> deðilse iþlem-1'in yapýlmasýný istiyorum. Ancak x deðeri 9 a eþit bir
> deðiþken girip sorguyu çaðýrdýðýmda iþlem-2 deðil yine de iþlem-1
> yapýlýyor. Nerede hata yapýyorum acaba? Bu arada sorguyu þu þekilde
> yaptýðýmda doðru çalýþýyor;
>
> if ((mysql_num_rows($result)&amp;lt;1) or ($x != 9))
>
> Saygýlarýmla..
>
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> </blockquote>
> <pre wrap=""><!---->
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Received on Mon 09 Mar 2009 - 14:20:35 EET