Re: Re: [Linux-programlama] PHP ile While Döngü Sorusu

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From: Volkan KIRIK (volkirik@yahoo.com.tr)
Date: Mon 05 Jun 2006 - 13:05:18 GMT


$count++ sonunada bi tane koymayi dene

----- Original Message -----
From: "Erdal YAZICIOGLU" <erdal.yazicioglu@gmail.com>
To: <linux-programlama@liste.linux.org.tr>
Sent: Monday, June 05, 2006 3:59 PM
Subject: Re: [Linux-programlama] PHP ile While Döngü Sorusu

> Bu seferde line 14'de aynı hatayı verdi...
>
>
>
>
> ----- Original Message -----
> From: "Volkan KIRIK" <volkirik@yahoo.com.tr>
> To: <linux-programlama@liste.linux.org.tr>
> Sent: Monday, June 05, 2006 3:53 PM
> Subject: Re: [Linux-programlama] PHP ile While Döngü Sorusu
>
>
>> $count=1 den sonra noktali virgul koyun,
>> sorun cozulecektir sanirim
>>
>> iyi calismalar
>>
>> ----- Original Message -----
>> From: "Erdal YAZICIOGLU" <erdal.yazicioglu@gmail.com>
>> To: <linux-programlama@liste.linux.org.tr>
>> Sent: Monday, June 05, 2006 3:50 PM
>> Subject: [Linux-programlama] PHP ile While Döngü Sorusu
>>
>>
>>> Merhabalar,
>>>
>>> Veritabanımda 401 adet daire kayıtlı ve bu daireleri kutu içerisinde her
>>> satıra 20 adet felecek şekilde ekrana dökmek istiyorum. Aşağıdaki gibi
>>> bir
>>> kod yazdım ancak bir türlü } hatasını aşamadım.. Yardımcı olursanız
>>> sevinirim... parantezi kaldırsamda atnı problem devam etmekte...
>>>
>>> Saygılar
>>>
>>> <?php
>>> $link = mysql_connect("localhost","root","cimbom");
>>> mysql_select_db("polattower", $link) or die(mysql_error());
>>> $count = 1;
>>>
>>> $query="select * from apartments";
>>> $result = mysql_query($query) or die(mysql_error());
>>> while($row = mysql_fetch_array($result)):
>>> if($count==20) {
>>> echo "<td>" . $arr['aparmentID'] . "</td>";
>>> $count=1
>>> }
>>> else
>>> {
>>> $count++
>>> }
>>> endwhile;
>>> ?>
>>>
>>>
>>>
>>> HATA :Parse error: parse error, unexpected '}' in
>>> C:\Inetpub\wwwroot\polat\db.php on line 12
>>>
>>>
>>>
>>>
>>
>>
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>>
>>
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>>
>
>
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