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NET MASK
1-) Mesela, 193.140.65.0 olan bir C-Sinifi IP, 255.255.255.192
net maskiyla, nasil 4 parcaya bolunur ?
Buradaki mask i ele alacak olursak,
255.255.255.192 = 11111111.11111111.11111111.11000000
------------Network---------- Host
Host alanina bakarsak
us--> 0 1 2 3 4 5
000000 karsiligi = 2 + 2 + 2 + 2 + 2 + 2 = 1+2+4+8+16+32 = 63
IP networklerinde 3 ayri numara kullanilir , 1-network numarasi,
2-Host numarasi, 3-Broadcast numarasi
192 subnetine geri donersek eger,
193.140.65.0 numarali network
193.140.65.1 - 193.140.65.62 nolu adreslerden
193.140.65.64 numarali network
193.140.65.65 - 193.140.65.126 nolu adreslerden
193.140.65.128 numarali network
193.140.65.129 - 193.140.65.190 nolu adreslerden
193.140.65.192 numarali network
193.140.65.193 - 193.140.65.254 nolu adreslerden olusur.
Her grubun sonundaki adres ise (63, 127, 191 ,255) broadcast adresidir.
2-) Peki, 255.255.255.254 subneti , kac alt ag adresleyebilir?
En kucuk subnet kullanilabilecek mask
255.255.255.252 = 11111111.11111111.11111111.11111100
------------Network--------------Host
3-) Hangi subnet numarasinin kac aga boldugunu hesaplamanin yolu nedir??
Son digitlere bakip hesaplayabilirsin veya kuracagin segmentte
bulunan max. host sayisina gore karar verirsin, Ornegin
16 hosttan olusan networkler (16 adet)icin 256-16 = 240
32 hosttan olusan networkler (8 adet) icin 256-32 = 224
64 hosttan olusan networkler (4 adet) icin 256-64 = 192
Daha komplex subnet ornekleri ve detayli bilgi icin ilgili RFC,
Internetworking with TCP/IP Douglas Comer,veya TCP/IP network
administration Craig Hunt in kitaplarini tavsiye ederim.
Date: Wed, 24 May 95 18:46:27 +0200
From: Kursat Cagiltay <kursat@knidos.cc.metu.edu.tr>
To: Multiple recipients of list <inet-tr@metu.edu.tr>
----
Murat Balci UNIX sys. Admin http://bornova.ege.edu.tr/~balci
s-mail : Ege Universitesi B.A.U.M - Bornova, IZMIR, TURKIYE.
e-mail : balci@bornova.ege.edu.tr Phone :+(90)(232)3881080-253